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DIY Project Time Estimator

DIY Project Time Estimator calculates time, efficiency, and resource sufficiency for DIY projects based on complexity, skill, and tools.

Formulas Used in DIY Project Time Estimator

The calculator uses the following formulas to estimate project time:

Estimated Project Time:

\\[ T_p = C \cdot \frac{1}{S_l \cdot T_a} \cdot M_p \\]

Efficiency Factor:

\\[ E_f = \min\left(100 \cdot \frac{S_l \cdot T_a}{M_p}, 100\right) \\]

Resource Sufficiency:

\\[ R_s = \min\left(100 \cdot \frac{S_l \cdot T_a}{C \cdot R_{\text{max}}}, 100\right) \\]

Where:

  • \\( T_p \\): Estimated project time (hours)
  • \\( C \\): Project complexity (1–10)
  • \\( S_l \\): Skill level multiplier (Beginner: 0.6, Intermediate: 1.0, Expert: 1.4)
  • \\( T_a \\): Tool availability multiplier (Basic: 0.7, Moderate: 1.0, Advanced: 1.3)
  • \\( M_p \\): Project type multiplier (Woodworking: 1.0, Painting: 0.8, Electronics: 1.2)
  • \\( E_f \\): Efficiency factor (%)
  • \\( R_s \\): Resource sufficiency (%)
  • \\( R_{\text{max}} \\): Maximum reference resource factor (2.0)

Example Calculations

Example 1: Simple Project, Beginner Skill, Basic Tools, Woodworking

Input: Project Complexity = 3, Skill Level = Beginner, Tool Availability = Basic, Project Type = Woodworking

\\[ T_p = C \cdot \frac{1}{S_l \cdot T_a} \cdot M_p = 3 \cdot \frac{1}{0.6 \cdot 0.7} \cdot 1.0 = 7.14 \ \text{hours} \\] \\[ E_f = \min\left(100 \cdot \frac{S_l \cdot T_a}{M_p}, 100\right) = \min\left(100 \cdot \frac{0.6 \cdot 0.7}{1.0}, 100\right) = 42 \ \% \\] \\[ R_s = \min\left(100 \cdot \frac{S_l \cdot T_a}{C \cdot R_{\text{max}}}, 100\right) = \min\left(100 \cdot \frac{0.6 \cdot 0.7}{3 \cdot 2.0}, 100\right) = 7 \ \% \\]

Result: Estimated Project Time: 7.14 hours, Efficiency Factor: 42%, Resource Sufficiency: 7%

Example 2: Moderate Project, Intermediate Skill, Moderate Tools, Painting

Input: Project Complexity = 5, Skill Level = Intermediate, Tool Availability = Moderate, Project Type = Painting

\\[ T_p = C \cdot \frac{1}{S_l \cdot T_a} \cdot M_p = 5 \cdot \frac{1}{1.0 \cdot 1.0} \cdot 0.8 = 4 \ \text{hours} \\] \\[ E_f = \min\left(100 \cdot \frac{S_l \cdot T_a}{M_p}, 100\right) = \min\left(100 \cdot \frac{1.0 \cdot 1.0}{0.8}, 100\right) = 100 \ \% \\] \\[ R_s = \min\left(100 \cdot \frac{S_l \cdot T_a}{C \cdot R_{\text{max}}}, 100\right) = \min\left(100 \cdot \frac{1.0 \cdot 1.0}{5 \cdot 2.0}, 100\right) = 10 \ \% \\]

Result: Estimated Project Time: 4 hours, Efficiency Factor: 100%, Resource Sufficiency: 10%

Example 3: Complex Project, Expert Skill, Advanced Tools, Electronics

Input: Project Complexity = 8, Skill Level = Expert, Tool Availability = Advanced, Project Type = Electronics

\\[ T_p = C \cdot \frac{1}{S_l \cdot T_a} \cdot M_p = 8 \cdot \frac{1}{1.4 \cdot 1.3} \cdot 1.2 = 5.27 \ \text{hours} \\] \\[ E_f = \min\left(100 \cdot \frac{S_l \cdot T_a}{M_p}, 100\right) = \min\left(100 \cdot \frac{1.4 \cdot 1.3}{1.2}, 100\right) = 100 \ \% \\] \\[ R_s = \min\left(100 \cdot \frac{S_l \cdot T_a}{C \cdot R_{\text{max}}}, 100\right) = \min\left(100 \cdot \frac{1.4 \cdot 1.3}{8 \cdot 2.0}, 100\right) = 11.38 \ \% \\]

Result: Estimated Project Time: 5.27 hours, Efficiency Factor: 100%, Resource Sufficiency: 11.38%

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