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Freelance Project Time Estimator

Freelance Project Time Estimator predicts project hours, efficiency, and confidence score from tasks, complexity, and buffer for effective time planning.

Formulas Used in Freelance Project Time Estimator

The calculator uses the following formulas to estimate project time:

Total Task Hours per Task Type:

\[ H_t = N \cdot H_a \cdot F_c \]

Total Project Hours:

\[ H_p = \sum H_t + (H_b \cdot \sum H_t) \]

Task Completion Efficiency:

\[ E = \frac{\sum H_t}{H_p} \cdot 100 \]

Project Completion Confidence Score:

\[ S = \min\left(100 \cdot \frac{T_{\text{max}} – H_p}{T_{\text{max}}}, 100\right) \]

Where:

  • \( H_t \): Total hours for a task type (hours)
  • \( N \): Number of tasks
  • \( H_a \): Average hours per task (hours)
  • \( F_c \): Complexity factor (Low: 1.0, Medium: 1.5, High: 2.0)
  • \( H_p \): Total project hours (hours)
  • \( H_b \): Contingency buffer (decimal)
  • \( E \): Task completion efficiency (%)
  • \( S \): Project completion confidence score (%)
  • \( T_{\text{max}} \): Maximum reference hours (500 hours)

Example Calculations

Example 1: Small Project, Single Task Type, Low Complexity

Input: Task Types = 1 (Tasks: 10, Hours/Task: 5, Complexity: Low), Contingency Buffer = 20%

\[ H_{t1} = N \cdot H_a \cdot F_c = 10 \cdot 5 \cdot 1.0 = 50 \ \text{hours} \] \[ H_p = \sum H_t + (H_b \cdot \sum H_t) = 50 + (0.2 \cdot 50) = 60 \ \text{hours} \] \[ E = \frac{\sum H_t}{H_p} \cdot 100 = \frac{50}{60} \cdot 100 = 83.33 \ \% \] \[ S = \min\left(100 \cdot \frac{T_{\text{max}} – H_p}{T_{\text{max}}}, 100\right) = \min\left(100 \cdot \frac{500 – 60}{500}, 100\right) = 88 \ \% \]

Result: Task Type 1: 50 hours, Total Project Hours: 60 hours, Efficiency: 83.33%, Confidence Score: 88%

Example 2: Medium Project, Three Task Types, Mixed Complexity

Input: Task Types = 3 (Type 1: 10 tasks, 5 hours, Low; Type 2: 15 tasks, 8 hours, Medium; Type 3: 5 tasks, 10 hours, High), Contingency Buffer = 25%

\[ H_{t1} = 10 \cdot 5 \cdot 1.0 = 50 \ \text{hours} \] \[ H_{t2} = 15 \cdot 8 \cdot 1.5 = 180 \ \text{hours} \] \[ H_{t3} = 5 \cdot 10 \cdot 2.0 = 100 \ \text{hours} \] \[ H_p = \sum H_t + (H_b \cdot \sum H_t) = (50 + 180 + 100) + (0.25 \cdot 330) = 330 + 82.5 = 412.5 \ \text{hours} \] \[ E = \frac{\sum H_t}{H_p} \cdot 100 = \frac{330}{412.5} \cdot 100 = 80 \ \% \] \[ S = \min\left(100 \cdot \frac{T_{\text{max}} – H_p}{T_{\text{max}}}, 100\right) = \min\left(100 \cdot \frac{500 – 412.5}{500}, 100\right) = 17.5 \ \% \]

Result: Task Type 1: 50 hours, Task Type 2: 180 hours, Task Type 3: 100 hours, Total Project Hours: 412.5 hours, Efficiency: 80%, Confidence Score: 17.5%

Example 3: Large Project, Five Task Types, High Complexity

Input: Task Types = 5 (Type 1: 20 tasks, 10 hours, High; Type 2: 15 tasks, 8 hours, Medium; Type 3: 10 tasks, 5 hours, Low; Type 4: 12 tasks, 7 hours, Medium; Type 5: 8 tasks, 6 hours, High), Contingency Buffer = 30%

\[ H_{t1} = 20 \cdot 10 \cdot 2.0 = 400 \ \text{hours} \] \[ H_{t2} = 15 \cdot 8 \cdot 1.5 = 180 \ \text{hours} \] \[ H_{t3} = 10 \cdot 5 \cdot 1.0 = 50 \ \text{hours} \] \[ H_{t4} = 12 \cdot 7 \cdot 1.5 = 126 \ \text{hours} \] \[ H_{t5} = 8 \cdot 6 \cdot 2.0 = 96 \ \text{hours} \] \[ H_p = \sum H_t + (H_b \cdot \sum H_t) = (400 + 180 + 50 + 126 + 96) + (0.3 \cdot 852) = 852 + 255.6 = 1107.6 \ \text{hours} \] \[ E = \frac{\sum H_t}{H_p} \cdot 100 = \frac{852}{1107.6} \cdot 100 = 76.92 \ \% \] \[ S = \min\left(100 \cdot \frac{T_{\text{max}} – H_p}{T_{\text{max}}}, 100\right) = \min\left(100 \cdot \frac{500 – 1107.6}{500}, 100\right) = 0 \ \% \]

Result: Task Type 1: 400 hours, Task Type 2: 180 hours, Task Type 3: 50 hours, Task Type 4: 126 hours, Task Type 5: 96 hours, Total Project Hours: 1107.6 hours, Efficiency: 76.92%, Confidence Score: 0%

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