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Warehouse Storage Optimizer

Warehouse Storage Optimizer allocates space for items based on volume, priority, and stacking efficiency to maximize utilization and accessibility.

Formulas Used in Warehouse Storage Optimizer

The calculator uses the following formulas to optimize storage allocation:

Effective Item Volume:

\\[ V_i^{\text{eff}} = V_i \cdot S \\]

Priority Weight:

\\[ W_i = P_i \\]

Total Weight:

\\[ W_{\text{total}} = \sum W_i \\]

Allocated Volume per Item:

\\[ A_i = \min\left(V_i^{\text{eff}}, \frac{W_i}{W_{\text{total}}} \cdot V_{\text{warehouse}} \cdot A_{\text{factor}}\right) \\]

Total Allocated Volume:

\\[ A_{\text{total}} = \sum A_i \\]

Space Utilization Score:

\\[ U = \min\left(100 \cdot \frac{A_{\text{total}}}{V_{\text{warehouse}}}, 100\right) \\]

Where:

  • \\( V_i^{\text{eff}} \\): Effective volume for item \\( i \\) (cubic meters)
  • \\( V_i \\): Base volume of item \\( i \\) (cubic meters)
  • \\( S \\): Stacking factor (Loose: 0.8, Standard: 0.9, Optimal: 1.0)
  • \\( W_i \\): Priority weight for item \\( i \\) (Low: 1, Medium: 2, High: 3)
  • \\( W_{\text{total}} \\): Sum of weights
  • \\( A_i \\): Allocated volume for item \\( i \\) (cubic meters)
  • \\( V_{\text{warehouse}} \\): Total warehouse volume (cubic meters)
  • \\( A_{\text{factor}} \\): Accessibility factor (0.9)
  • \\( A_{\text{total}} \\): Total allocated volume (cubic meters)
  • \\( U \\): Space utilization score (%)

Example Calculations

Example 1: Small Warehouse, Loose Stacking

Input: Items = 2 (Pallets: 200 m³, High; Boxes: 100 m³, Low), Warehouse Volume = 500 m³, Stacking = Loose

\\[ V_{\text{Pallets}}^{\text{eff}} = 200 \cdot 0.8 = 160 \ \text{m³}, \quad V_{\text{Boxes}}^{\text{eff}} = 100 \cdot 0.8 = 80 \ \text{m³} \\] \\[ W_{\text{Pallets}} = 3, \quad W_{\text{Boxes}} = 1 \\] \\[ W_{\text{total}} = 3 + 1 = 4 \\] \\[ A_{\text{Pallets}} = \min\left(160, \frac{3}{4} \cdot 500 \cdot 0.9\right) = \min(160, 337.5) = 160 \ \text{m³} \\] \\[ A_{\text{Boxes}} = \min\left(80, \frac{1}{4} \cdot 500 \cdot 0.9\right) = \min(80, 112.5) = 80 \ \text{m³} \\] \\[ A_{\text{total}} = 160 + 80 = 240 \ \text{m³} \\] \\[ U = 100 \cdot \frac{240}{500} = 48 \ \% \\]

Result: Pallets: 160 m³, Boxes: 80 m³, Total Allocated: 240 m³, Utilization: 48%

Example 2: Medium Warehouse, Standard Stacking

Input: Items = 3 (Pallets: 300 m³, High; Boxes: 200 m³, Medium; Crates: 100 m³, Low), Warehouse Volume = 1000 m³, Stacking = Standard

\\[ V_{\text{Pallets}}^{\text{eff}} = 300 \cdot 0.9 = 270 \ \text{m³}, \quad V_{\text{Boxes}}^{\text{eff}} = 200 \cdot 0.9 = 180 \ \text{m³}, \quad V_{\text{Crates}}^{\text{eff}} = 100 \cdot 0.9 = 90 \ \text{m³} \\] \\[ W_{\text{Pallets}} = 3, \quad W_{\text{Boxes}} = 2, \quad W_{\text{Crates}} = 1 \\] \\[ W_{\text{total}} = 3 + 2 + 1 = 6 \\] \\[ A_{\text{Pallets}} = \min\left(270, \frac{3}{6} \cdot 1000 \cdot 0.9\right) = \min(270, 450) = 270 \ \text{m³} \\] \\[ A_{\text{Boxes}} = \min\left(180, \frac{2}{6} \cdot 1000 \cdot 0.9\right) = \min(180, 300) = 180 \ \text{m³} \\] \\[ A_{\text{Crates}} = \min\left(90, \frac{1}{6} \cdot 1000 \cdot 0.9\right) = \min(90, 150) = 90 \ \text{m³} \\] \\[ A_{\text{total}} = 270 + 180 + 90 = 540 \ \text{m³} \\] \\[ U = 100 \cdot \frac{540}{1000} = 54 \ \% \\]

Result: Pallets: 270 m³, Boxes: 180 m³, Crates: 90 m³, Total Allocated: 540 m³, Utilization: 54%

Example 3: Large Warehouse, Optimal Stacking

Input: Items = 5 (Pallets: 1000 m³, High; Boxes: 800 m³, High; Crates: 600 m³, Medium; Drums: 400 m³, Medium; Bags: 200 m³, Low), Warehouse Volume = 3000 m³, Stacking = Optimal

\\[ V_{\text{Pallets}}^{\text{eff}} = 1000 \cdot 1.0 = 1000 \ \text{m³}, \quad V_{\text{Boxes}}^{\text{eff}} = 800 \cdot 1.0 = 800 \ \text{m³}, \quad V_{\text{Crates}}^{\text{eff}} = 600 \cdot 1.0 = 600 \ \text{m³} \\] \\[ V_{\text{Drums}}^{\text{eff}} = 400 \cdot 1.0 = 400 \ \text{m³}, \quad V_{\text{Bags}}^{\text{eff}} = 200 \cdot 1.0 = 200 \ \text{m³} \\] \\[ W_{\text{Pallets}} = 3, \quad W_{\text{Boxes}} = 3, \quad W_{\text{Crates}} = 2, \quad W_{\text{Drums}} = 2, \quad W_{\text{Bags}} = 1 \\] \\[ W_{\text{total}} = 3 + 3 + 2 + 2 + 1 = 11 \\] \\[ A_{\text{Pallets}} = \min\left(1000, \frac{3}{11} \cdot 3000 \cdot 0.9\right) = \min(1000, 818.18) = 818.18 \ \text{m³} \\] \\[ A_{\text{Boxes}} = \min\left(800, \frac{3}{11} \cdot 3000 \cdot 0.9\right) = \min(800, 818.18) = 800 \ \text{m³} \\] \\[ A_{\text{Crates}} = \min\left(600, \frac{2}{11} \cdot 3000 \cdot 0.9\right) = \min(600, 545.45) = 545.45 \ \text{m³} \\] \\[ A_{\text{Drums}} = \min\left(400, \frac{2}{11} \cdot 3000 \cdot 0.9\right) = \min(400, 545.45) = 400 \ \text{m³} \\] \\[ A_{\text{Bags}} = \min\left(200, \frac{1}{11} \cdot 3000 \cdot 0.9\right) = \min(200, 272.73) = 200 \ \text{m³} \\] \\[ A_{\text{total}} = 818.18 + 800 + 545.45 + 400 + 200 = 2763.64 \ \text{m³} \\] \\[ U = 100 \cdot \frac{2763.64}{3000} \approx 92.1 \ \% \\]

Result: Pallets: 818.18 m³, Boxes: 800 m³, Crates: 545.45 m³, Drums: 400 m³, Bags: 200 m³, Total Allocated: 2763.64 m³, Utilization: 92.1%

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